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An analyst is using the data in the foll...

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题目

An analyst is using the data in the following exhibit to prepare a statistical report.「huixue_img/importSubject/1564548690960584704.png」The cumulative relative frequency for the bin -1.71% ≤ x < 2.03% is closest to:

选项

A.0.250.

B.0.333.

C.0.583.

答案

C

解析

C is correct. The cumulative relative frequency of a bin identifies the fraction of observations that are less than the upper limit of the given bin. It is determined by summing the relative frequencies from the lowest bin up to and including the given bin. The following exhibit shows the relative frequencies for all the bins of the data from the previous exhibit:「huixue_img/importSubject/1564548691048665088.png」The bin -1.71% ≤ x < 2.03% has a cumulative relative frequency of 0.583.
. 根据题目中表格信息,题目问:区间-1.71% ≤ x < 2.03%对应的累积相对频率是多少?一个区间的累积相对频率,应该包含“小于给定区间上限”的观测值的部分。它是由最低区间到并包括给定区间的相对频率之和决定的。表中显示了题目表中所有数据区间的相对频率。区间-1.71% ≤ x < 2.03%对应的累积相对频率为0.583。 补充: 数据中的最大值和最下值可以找到,差值为9.47-(-9.19)=18.66 题目问的一个区间是-1.71至2.03,差值为3.74 于是18.66可以分成?个3.74的区间呢?18.66/3.74=5个 第一个upper limit是-5.45=-9.19+3.74