题目
You would like to describe an account that begins at TIME(0) = $100.00 and compounds continuously at 9.0% per annum. What is a function that characterizes the value of this account ,A(t), over time according to such a continuous and constant growth trend?
选项
A.A(t)=$100*e^(0.090*TIME(t))
B.ln[A(t)]=ln($100)+0.09*TIME(t)
C.Neither (A) nor (B)
D.Both (A) and (B)
答案
D
解析
A(t)=β(0)+ eβ(1)×TIME(t) describes an exponential (aka, log-linear) trend that is growing at a continuous rate of β(1); in this case, β(0) is the initial value of $100.00 and β(1) is the growth rate of 9.0%. Then we can also take the natural log of both sides and observe thatLN[A(t)] is a linear function of time:LN[A(t)]=LN(β(0)×eβ(1)×TIME(t) )= LN[β(0)] +LN(eβ(1)×TIME(t) )= LN[β(0)]+ β(1)×TIME(t) ).